Math, asked by gvdeveshwar, 11 months ago

3. I think of a number and subtract
n it. I multiply
the
result by 8 and the result I finally obtain is 3 times
the same number I thought of The number is?

pls answer I give 50pts

Answers

Answered by Anonymous
1

Answer:

Let the no. she thought be y

equation = 8(y-5/2) = 3y

= (8y-40/2)=3y

= 8y-6y=40

= 2y=40

= y=20

Therefore the no. she thought is 20

Answered by Avni2348
0

Step-by-step explanation:

Hiii friend,

Let the denominator of the fraction be X.

Then the numerator of the fraction = (X-3)

Fraction = Numerator/Denominator = X-3/X.

Numerator and denominator are increased by 2 then the Numerator and denominator becomes (X-3+2) and (X+2).

Fraction = Numerator/Denominator =(X-3+2)/(X+2).

According to question,

(X-3+2)/(X+2) = 6/7

X-1/X+2 = 6/7

7(X-1) = 6(X+2)

7X-7 = 6X+12

7X-6X= 12+7

X = 19

Numerator = (X-3) = (19-3) = 16

And,

Denominator =(X) = 19

Therefore,

Original Fraction = Numerator/Denominator = (X-3)/X= 19/16

Similar questions