3 identical cells each of EMf=2V internal resistence 0.2 ohm
are connected in series to an external resistance7.4 ohm
Calculate the current in the circuit
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0.75 Ampere
Explanation:
V = 2V×3
= 6V
R = 0.2× 3 + 7.4
= 0.6 + 7.4
= 8.0 ohm
Now,
R = V/I
I = V/R
= 6/8
Ans: = 0.75 ohm
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