Physics, asked by akshat546217, 11 months ago

3 identical cells each of EMf=2V internal resistence 0.2 ohm
are connected in series to an external resistance7.4 ohm
Calculate the current in the circuit​

Answers

Answered by pranav7124
2

0.75 Ampere

Explanation:

V = 2V×3

= 6V

R = 0.2× 3 + 7.4

= 0.6 + 7.4

= 8.0 ohm

Now,

R = V/I

I = V/R

= 6/8

Ans: = 0.75 ohm

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