3 identical cells each of emf 4 Volt & internal resistance r are connected in series to a 6 ohms resistor. If the current flowing in the circuit is 1.5A then calculate internal resistance of each cell & the terminal voltage across the cells
class 12
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Answer:
Three identical cells, each of 4 V and internal resistance r, are connected in series to a 6 ohm resistor. If the current flowing in the circuit is 2 A. The internal resistance of each cell is 0.11 ohm.
Explanation:
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Answered by
0
Answer:
e=ir
12=2(6+3r)
6=6+3r
o=3r
r=o
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