Question

3]if 1/x+2, 1/x+3, 1/x+5, are in ap then find x​

Answer 1

Since 1/x+2 ,1/x+3, 1/x+5 are in AP

2/x+3= 1/ x+2 + 1/ x+5 =2x+7/ (x+2)(x+5)

2(x+2)(x+5)=(x+3)(2x+7)

2(x^+7x+10)=2x^2+13x+21

2x^2+14x+20=2x^2+13x+21

x= 1

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