Question

3. If 1500 joule of energy is released when a substance of mass 150 gm
cools from 140°C to 80'C. Then calculate (a) specific heat, (b)
thermal capacity, (c) Water equivalent of the substance.​

Answer 1

Answer:

heat energy = (mass) × (heat capacity) × (change in temperature)

Q=m×C×ΔT

Q=150g×4.18J/gK×(25−5)K=12540 J