Question

3. If 2 is a zero of the polynomial p(x) = x3 - 2kx2 + kr - 1, find the value of k.​

Answer 1

Step-by-step explanation:

p(x) = x3 -2k x2 +kr - 1

p(2) = (2)3- 2k (2)2 + kr -1

= 6 - 2k ×4 + kr -1

= 4k ×4 + kr -1

= 24k + kr -1

= 23 k +kr

LET K BE 1 OR X

=23 k + kr

= 23( x) or (1) + (1)

= 23 + 1

= 24

THEREFORE K = 24