Question

3. If 2 sin2 0 -cos2 0 = 2, then the value of 0 is:
(a) 90°
(d) 0°
(c) 45°
(d) 36°​

Answer 1

Answer:

90°

Step-by-step explanation:

$2sin^2\theta-cos^2\theta=2\\=>2sin^2\theta-(1-sin^2\theta)=2\\=>2sin^2\theta+sin^2\theta-1=2\\=>3sin^2\theta=3\\=>sin^2\theta=1\\=>sin\theta=1\\=>sin\theta=sin90degree\\=>\theta=90degree$

edit: mark it as the brainliest please ....