3. If 2x, x + 10, 3x + 2 are in A.P., find the value of x.
Standard:- 10
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3
Hey
Here is your answer,
A.P : 2x, x+10 , 3x+2
In an A.P. Second term - first term = third term - second term
x+10-(2x) = 3x+2-(x+10)
x+10-2x = 3x+2-x -10
10-x = 2x -8
-x -2x=-8-10
-3x=-18
x=-18/-3
x=6
Terms = 2x = 12
X+10 = 16
3x+2 = 18+2 = 20
Hope it helps you!
Here is your answer,
A.P : 2x, x+10 , 3x+2
In an A.P. Second term - first term = third term - second term
x+10-(2x) = 3x+2-(x+10)
x+10-2x = 3x+2-x -10
10-x = 2x -8
-x -2x=-8-10
-3x=-18
x=-18/-3
x=6
Terms = 2x = 12
X+10 = 16
3x+2 = 18+2 = 20
Hope it helps you!
Answered by
2
Hey mate,
Here is ur answer,
2x , x+10 , 3x+2.
In AP common difference is constant.
=> a2-a1 = a3-a2.
=> x+10-2x= 3x+2-x-10.
=> 10-x = 2x-8
=> 3x =18.
=> x=18/3.
=> x=6
:-)Hope it helps u. 《《 VIDYA 》》
Here is ur answer,
2x , x+10 , 3x+2.
In AP common difference is constant.
=> a2-a1 = a3-a2.
=> x+10-2x= 3x+2-x-10.
=> 10-x = 2x-8
=> 3x =18.
=> x=18/3.
=> x=6
:-)Hope it helps u. 《《 VIDYA 》》
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