Question

3) If 4× 10−3 joule of work is done in moving a particle carrying a charge 16 × 10−6from infinity to a
point P what will be the potential at point P?
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Answer 1

potential difference= work/charge , Vinfinty-Vp= 4×10^-3/16×10^-6 , here at infinity potential is zero so , 0-Vp= 4×10^-3+6/16 , -Vp=1000/4 then Vp= -250 volt