Question

3. If 4x2– 8x + 3 = 0 then x =1/2 y find the value of y = _
пX:​

Answer 1

Step-by-step explanation:

${4x}^{2} - 8x + 3 \\ = 4( \frac{y {}^{2} }{4} ) - 8( \frac{y}{2} ) + 3 = 0 \\ {y}^{2} - 4y + 3 = 0 \\ = {y}^{2} - 3y - y + 3 = 0 \\ = y(y - 3) - 1(y - 3) \\ = y = 1 \: or \: 3$