Question

3) If a=3 ,b=2, C = 1, find the value
3 ab + 2a2b-4abc

Answer 1

Answer:

Answer:

Required numeric value of the given equation is 5.

Step-by-step explanation:

Given numeric values of a , b and c are 3 , 2 and - 1 respectively.

Equation to be simplified is ab^2 + bc^2 + ca^2 , in order to simplify we have to substitute the given numeric values of a, b and c.

Thus,

= > ab^2 + bc^2 + ca^2

= > ( 3 )( 2 )^2 + ( 2 )( - 1 )^2 + ( - 1 )( 3 )^2

We know, square of any negative number is as same as square of that number with positive number. Also, when we multiply two negative number, the resultant number is positive number.

Therefore,

= > ( 3 )( 4 ) + ( 2 )( 1 ) + ( - 1 )( 9 )

= > 12 + 2 - 9

= > 3 + 2

= > 5

Hence, the required numeric value of the given equation is 5.

Answer 2

Answer:

The answer is 4

Step-by-step explanation:

= 3 x a x b x c + 2 x a x 2 x b - 4 x a x b x c

= 3 x 3 x 2 x 1 + 2 x 3 x 2 x 2 - 4 x 3 x 2 x 1

= (18 + 10) - 24

= 28 - 24

= 4