3) If a=3 , b = 2, C = 1, find the value
3 ab + 2a2b -4abc
shivamsharma10117:
hloo
3a + b + 2c = 3 … Eq. (1)
a + 3b + 2c = 1 … Eq. (2)
Subtract Eq. (2) from Eq. (1) and you get
2a - 2b = 2, or a - b = 1
Thus b = a - 1
Put this value of b in Eq. (1) to get 3a + a - 1 + 2c = 3 or 4a + 2c = 4
So. 2a + c = 2.
a + 3b + 2c = 1 … Eq. (2)
Subtract Eq. (2) from Eq. (1) and you get
2a - 2b = 2, or a - b = 1
Thus b = a - 1
Put this value of b in Eq. (1) to get 3a + a - 1 + 2c = 3 or 4a + 2c = 4
So. 2a + c = 2.
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Step-by-step explanation:
so your answer is 18
hope its helpful
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Answer:
3ab +2a²b -4abc
Putting the given values
3(3)(2)+2(3)²(2)-4(2)(1)
→18+ 36 - 8
→54-8
→46
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