Question

3. If (a+b+4) =0, then a² + b² + 16 is: (uf (a+b+4) =0, T a'+b? + 16 )​

Answer 1

Answer:

26

Step-by-step explanation:

Method 1: Squaring & adding the given equations a+b=6 & a−b=4 , one should get

(a+b)2+(a−b)2=62+42

a2+b2+2ab+a2+b2−2ab=36+16

2(a2+b2)=52

a2+b2=522=26

Method 2: Adding the given equations: a+b=6 & a−b=4 ⟹a+b+a−b=6+4⟹a=5

Now, subtracting given equations: a+b−a+b=6−4⟹b=1

∴a2+b2=52+12=25+1=26

hope this will help you....