Question

3 If a + b + c=0 then find a²/bc + b²/ca + c²/ab=?​

Answer 1

Answer:

3

Step-by-step explanation:

Given,  

a+b+c=0

we know that,

if a+b+c=0, then a³+b³+c³=3abc

Now,

(a²/bc)+(b²/ac)+(c²/ab)=(a³+b³+c³)/abc

                                  = 3abc/abc

                                  =3

Answer 2

Answer:3

Step-by-step explanation:

Given a + b + c = 0

⇒ a3 + b3 + c3 = 3abc  → (1)

Consider, (a2/bc) + (b2/ca) + (c2/ab)

= (a3 + b3 + c3)/abc

= 3abc/abc = 3   [From (1)]