Question

3. If a + b + c = 8 and a2 + b2 + c2 = 34, find the value of a3 + b3 + c

3 – 3abc.​

Answer 1

Answer:

a3 + b3 + c3 = 152

3- 3abc = 0

Answer 2

Answer:

Step-by-step explanation:

a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ac)

a³+b³+c³-3abc = (8)(34- (ab+bc+ac))-------------------1

(a+b+c)² = a²+b²+c²-2ab-2bc-2ac

8² = 34 -2(ab+bc+ac)

64-34= -2 (ab+bc+ac)

30 / -2 =  (ab+bc+ac)

-15 = (ab+bc+ac) ------------------------------2

SUBSTITUTE 2 IN 1

a³+b³+c³-3abc = 8(34-(-15))

a³+b³+c³-3abc = 8(34+15)

a³+b³+c³-3abc = 8 *49

a³+b³+c³-3abc = 392

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