3. If a, b, c are in continued proportion, prove that:
(1)
(a+b+c) (a-b+c) = a^2 + b^2 +c^2
Answers
Answered by
2
Step-by-step explanation:
a:b:c
a×c=b^2------(1)
L.H.S.=(a+b+c)(a-b+c)
=a^2-ab+ac+ab-b^2+bc+ac-bc+c^2
= a^2-b^2+c^2 +2ac
a×c=b^2 -----from 1
hence,
a^2-b^2+c^2+2b^2
= a^2+b^2+c^2
R.H.S.= a^2+b^2+c^2
thus,
(a +b+c)(a-b+c)=a ^2+b^2+c^2
hope it is Helpful.
Answered by
0
Answer:
Step-by-step explanation:
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