Question

3. If a gas has n degrees of freedom, ratio of specific heats of gas is:
a) 1+1 b)1 + c)1 + 12 / d)1 + 2​

Answer 1

Question :-- If a gas has n degrees of freedom, ratio of specific heats of gas is ?

Formula used :--

→ Internal energy of one mole of gas = E = N(1/2 *n*KT) or = (1/2 * n * RT )

→ Cv = dE/dT = (n * R/2)

→ Cp = [n/2) + 1] * R

→ Specific Heat = Cv/Cp [ The specific heat ratio of a gas is commonly defined as the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume ] ..

Solution :--

Putting values we get,

→ Specific Heat = Cv/Cp

→ Specific Heat = (n * R/2) / [n/2) + 1] * R

→ Specific Heat = (n + 2) /n

or,

→ Specific Heat = n + (2/n) .