3. If A = {letters of the word RICE), B = {letters of the word NICE), find the following.
(1) AUB
(iii) AB
(in) BUA
(iv) BA
(v) A-B
(vi) B-A
m.et me rukane ko bola tha kaha gaye ab
only for my first following
Answers
Answer:
Given :-
A = {letters of the word RICE}
B = {letters of the word NICE}
To find :-
Find the following:
(1) AUB
(iii) AnB
(in) BUA
(iv) BnA
(v) A-B
(vi) B-A
Solution :-
Given sets are :
A = {letters of the word RICE}
=> A ={ R,I,C,E}
B = {letters of the word NICE}
=> B={N,I,C,E}
I)AUB:
=>AUB = { R,I,C,E} U {N,I,C,E}
AUB = { R,N,I,C,E}
ii)AnB:
=> AnB = { R,I,C,E} n {N,I,C,E}
AnB = { I,C,E}
iii) BUA :
=>BUA = {N,I,C,E} U{ R,I,C,E}
BUA ={ R,N,I,C,E}
iv) BnA:
=>BnA = {N,I,C,E} n{ R,I,C,E}
BnA={ I,C,E}
v)A-B:
=> A-B = { R,I,C,E} - {N,I,C,E}
A-B = { R}
vi) B-A:
=> B-A = {N,I,C,E} - { R,I,C,E}
B-A ={ N}
Answer :-
(1) AUB ={ R,N,I,C,E}
(iii) AnB ={I,C,E}
(in) BUA={ R,N,I,C,E}
(iv) BnA={I,C,E}
(v) A-B= {R}
(vi) B-A={N}
Observation :-
The following observations for the given problem are observed :
- AUB = BUA
- AnB = BnA
- A-B≠B-A
ANSWERS :-
(1) AUB={R,N,I,C,E}
(iii) AnB ={I,C,E}
(in) BUA={ R,N,I,C,E}
(iv) BnA={I,C,E}
(v) A-B= {R}
(vi) B-A={N}
OBSERVATION :-
The following observations for the given problem are observed :-
- •AUB = BUA
- AnB = BnA
- A-B*B-A