Question

3. If a number x is chosen from the numbers 1, 2, 3 and a number y is selected from the numbers 1, 4, 9, then find P(xy < 9).

Answer 1

Answer:

Number 'x' can be selected in three ways and corresponding to each such way there are three ways of selecting number y therefore, the two numbers can be selected in 9 ways as listed below:

(1,1),(1,4),(1,9),(2,1),(2,4),(2,9),(3,1),(3,4),(3,9)

Total number of outcomes =9

The product xy will be less than 9, if x and y are chosen in one of the following ways:

(1,1),(1,4),(2,1),(2,4),(3,1)

Number of favorable outcomes =5

P(product less than 9) =

9

5

Step-by-step explanation:

pls make it brain list and because it took time to type ans solve

Answer 2

Answer:

P(xy < 9) = $\frac{5}{9}$

Step-by-step explanation:

Number 'x' can be selected in 3 ways and corresponding to each such way Number 'y' can be selected in 3 ways. Thus the two numbers can be selected in 9 ways as:  (1,1), (1,4), (1,9), (2,1), (2,4), (2,9), (3,1), (3,4), (3,9)

Total number of outcomes = 9

The product xy will be less than 9, if x and y are chosen in one of the following ways:   (1,1), (1,4), (2,1), (2,4), (3,1)

Number of favorable outcomes =5

 P(xy < 9) = $\frac{5}{9}$