Question

3. If a parallelogram is cyclic, then prove that it is a rectangle.​

Answer 1

Answer:

Given,

ABCD is a cyclic parallelogram.

To prove,

ABCD is a rectangle.

Proof:

∠1+∠2=180° ...Opposite angles of a cyclic parallelogram

Also, Opposite angles of a cyclic parallelogram are equal.

Thus,

∠1=∠2

⇒∠1+∠1=180°

⇒∠1=90°

One of the interior angle of the parallelogram is right angled. Thus,

ABCD is a rectangle.

Step-by-step explanation:

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