Question

3. If a parallelogram is cyclic, then prove that it is a rectangle.​

Answer 1

Answer:

The ABCD is a cyclic parallelogram

Then ∠A=∠C (Opposite angle of parallelogram )

In cyclic parallelogram ABCD

∠A+∠C=180

0

(Sum of Opposite angle of cyclic parallelogram=180 degree )

⇒2∠A=180

0

⇒∠A=

2

180

=90

0

And ∠B=∠D (Opposite angle of parallelogram )

In cyclic parallelogram ABCD

∠B+∠D=180

0

(Sum of Opposite angle of cyclic parallelogram=180 degree )

⇒2∠B=180

0

⇒∠B=

2

180

=90

0

So in parallelogram ABCD all angle are right angle then ABCD is a rectangle

solution