3. If a=xy2 and b=x3y5 where x and y are prime numbers then LCM of (a, b) is
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Answer:
a = x × y × y
b = x × x × x × y × y × y × y × y.
LCM of ab =
x × y × y × x × x × y × y × y
= x3y5
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Answer:
a = x*y*h
a = x*y*hb =x*x*x*y*y*y*y*h
a = x*y*hb =x*x*x*y*y*y*y*hsince common multiple are x*y*y
a = x*y*hb =x*x*x*y*y*y*y*hsince common multiple are x*y*yso,
a = x*y*hb =x*x*x*y*y*y*y*hsince common multiple are x*y*yso, LCM (a,b) = xy^2
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