Math, asked by om828597, 8 months ago

3. If a=xy2 and b=x3y5 where x and y are prime numbers then LCM of (a, b) is

Answers

Answered by jackzzjck
7

Answer:

a = x × y × y

b = x × x × x × y × y × y × y × y.

LCM of ab =

x × y × y × x × x × y × y × y

= x3y5

Step-by-step explanation:

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Answered by laxita07
0

Answer:

a = x*y*h

a = x*y*hb =x*x*x*y*y*y*y*h

a = x*y*hb =x*x*x*y*y*y*y*hsince common multiple are x*y*y

a = x*y*hb =x*x*x*y*y*y*y*hsince common multiple are x*y*yso,

a = x*y*hb =x*x*x*y*y*y*y*hsince common multiple are x*y*yso, LCM (a,b) = xy^2

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