Question

3. If ABCD is a parallelogram, then prove that ar(ABD) = ar(BCD) = ar (ABC)
ar(ACD) = 1/2ar|lgm ABCD).
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Answer 1

Answer:

ABCD is a parallelogram.

When we join the diagonal of parallelogram, it divides it into two quadrilaterals

 Step 1:

Let AC is the diagonal, then, Area (ΔABC) = Area (ΔACD) = 1/2(Area of ||gm ABCD)

 Step 2:

Let BD be another diagonal  Area (ΔABD) = Area (ΔBCD) = 1/2( Area of llgm ABCD)

Now,  From Step 1 and step 2, we have  Area (ΔABC) = Area (ΔACD) = Area (ΔABD) = Area (ΔBCD) = 1/2(Area of llgm ABCD)

Hence Proved.

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Answer 2

Answer:

ABCD is a parallelogram.

When we join the diagonal of parallelogram, it divides it into two quadrilaterals.

Step 1: Let AC is the diagonal, then, Area (ΔABC) = Area (ΔACD) = 1/2(Area of ||gm ABCD)

Step 2: Let BD be another diagonal Area (ΔABD) = Area (ΔBCD) = 1/2( Area of llgm ABCD)

Now,

From Step 1 and step 2, we have Area (ΔABC) = Area (ΔACD) = Area (ΔABD) = Area (ΔBCD) = 1/2(Area of llgm (ABCD)

Step-by-step explanation:

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