Question

3. If an AP is 10, 7, 4, ....,- 62, find the 11th
term from its end.​

Answer 1

A(n)= a+(n-1)d
10+(n-1)d= -62
10+(n-1)-3=_62
10 -3n+3 =-62
-3n= -75
n= 15
11 th term from end = 15-11+1= 5
A(5)= a+4d
10-12=-2