3) If an atom has electronic configuration
1s^2 2s^2 2p^6 3s^2 3p^6 3d^3 4s^2, it will be placed in
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Atomic no. 23
name of the element : vanadium
it is placed with d- block elements.
in 5th group
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Answer:
Group 5 (Or) Group VB
Explanation:
This electronic configuration belongs to the neutral vanadium atom
The electronic configuration clearly suggest that it is a d-block element (having contiguration (n – 1) d1– 10 ns0 – 2). it belongs to the Group 5 because it's valency shell configuration is
V : [Ar ] 4 s² 3 d ³
where 2+3=5
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