3) Ifαandβarezeroesofp(x)=2x2+4kx+4,suchthatα2 +β2 = 12, find k.
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Answered by
0
Answer:
p(x)= 2x2+4kx+4
a2+b2=12
So,
a+b= -b/a
a+b=-4k/2
a+b=-2k
and,
ab= c/a
ab= 4/2
ab=2
Now,
(a+b)2= a2+b2+2ab
(-2k)2= 12+2×2
4k2=. 12+4
4k2=16
K2= 16/4
K2= 4
k=√4
(k= 2)
Answered by
3
Given that,
We know,
Also, we know that
According to statement,
Now, on substituting the values, we get
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