3. If (ax^3 + 2)^2 = a^2x^6 + x^3 +4, then find a
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If f ( x ) = x3 + ax ? – X – 2 and g ( x ) = ax3 + x2 – 6x – 4 are divided by ( x – 2 ) , the remainder is same .. Let x – 2 = 0 , then x = 2 Now R .
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★ Given :
- → If (ax³ + 2)² = a²x^6+ x³ +4, then find a.
★ To Find :
- → Value of a.
★ According to Question :
- → (ax³ + 2)² = a²x^6+ x³ +4
- → a²x^6 + 4 + 4ax³ = a²x^6 + x³ + 4
- → 4ax³ = x³
- → x³ ( 4a - 1 ) = 0
★ So Either x = 0 or 4a - 1 = 0 :
- → 4a - 1 = 0
- → 4a = 1
- → a = 1/4
★ Therefore :
- → The value of a is 1/4
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