Question

3.
If Ā+ B = C and Al2 + B12 = |C|2. then angle
between vectors A and B would be​

Answer 1

Step-by-step explanation:

First |A+B|^2=|C|^2 then √A^2 +B^2+2ABcostheta=C,C^2=A^2+B^2+2ABcos (theta). ,now a+b =c now squaring both sides (a+b)^2=c^2 ,=a^2+b^2 + 2ab=a^2+b^2+ cos (theta), 2ab cos (theta)=2ab , cos(theta)=1 so theta = 0 degreenso angle between a and b is 0 °