Question

3. If F is the force, m is the mass, v is the velocity the dimensions of X and Y on the relation

F=x(mv)/y+1 are respectively
(give answer with correct explanation)



(a) T ,T-1

(b) LT-1, L T-2

(c) T-1
,dimensionless
(d) dimensionless, T



❌warning don't want any useless answer❌
it's urgent​

Answer 1

Answer:

Let M = (some Number) (V)ª (F)b (T) Equating dimensions of both the sides M¹LºTº= (1) [L¹T-¹] [M¹L¹T-2]b[T¹] M¹LOTO MbLa+b = -a-2b+c

get a = -1, b = 1, c = 1

M = (Some Number) (V-¹F¹T¹) ⇒ [M] = [V-¹F¹T¹]

Similarly, we can also express energy in terms of V, F, T

Let [E] = [some Number] [V][F]b[T] → [ML²T-2] = [MOLOTO] [LT ¹][MLT-²]b[T]

[M¹L²T-2] = [M'La+by-a-2b+c

⇒1 = b; 2= a +b; -2=-a-2b + c

get a = 1; b = 1; c=1

.. E = (some Number) V¹F¹T¹ or [E] = [V¹] [F¹] [T¹]

Explanation:

Sorry I needed points

Answer 2

Answer:

... ... ...

Explanation:

Hi Ankita Unnie

hru?

Mich u!

kkrh?

exam still not over :(