Question

3. If f(t) = 4+² - 3t+6, find (i) f(0), (ii) f(4), (iii) f(-5) If ​

Answer 1

Answer:

maybe the ans is (iii)

Step-by-step explanation:

i hope it is helpful

Answer 2

Answer:

If f(t) = $4t^{2} - 3t + 6$ then (i) f(0) = 6 (ii) f(4) = 58 (iii) f(-5) = 121

Step-by-step explanation:

We have a function, first of all we need to understand what is function

Function- It is an expression which stablish realtion between two variable.

Now,

F(t) = $4t^{2} - 3t + 6$

We have to find f(0), f(4) and f(-5)

(i) We need to put t = 0

f(0) = $4*0^{2} -3*0 +6$

f(0) = 6

(ii) We need to put t = 4

f(4) = $4*4^{2} -3*4 + 6$

f(4) = 64-6 = 58

(iii) We need to put t = -5

f(-5) = $4*-5^{2} -3*(-5) + 6$

f(-5) = 100 + 15 + 6

f(-5) = 121

Final answer,

If f(t) = $4t^{2} - 3t + 6$, then

(i)f(0) = 6

(ii) f(4) = 58

(iii) f(-5) = 121