Question

3.
If g% of b + 1% of gb = 4% of (g + b), then the sum
of reciprocals of g and b is
​

Answer 1

Answer:

1/2

Step-by-step explanation:

g% of b = (g/100)*b

= gb/100

1% of gb = (1/100)*gb

= gb/100

4% of (g+b) = (4/100)*(g+b)

According to Question,

$\frac{gb}{100} + \frac{gb }{100} = \frac{4(g + b)}{100} \\ 2gb \: = 4(g + b) \\gb \: = 2g + 2b \\ dividing \: by \: 2gb \\ \frac{1}{2} = \frac{1}{b } + \frac{1}{g}$