Question

3. If n = 2 raise to 3 × 3 raise to 4 x 5 raise to 4 x7, then the number of consecutive zeros in n, where n is a
natural number, is
(a) 2
(b) 3
(c) 4
(d) 7
please give me a step by step explanation​

Answer 1

Step-by-step explanation:

n = 23 x 34 x 54 x 7

n = 23 x 34 x 53 x 5 x 7

n = (2 x 5)3 x 34 x 5 x 7

n = (10)3 x 34 x 5 x 7

n = 34 x 5 x 7 x 1000

Thus, in the given natural number 'n' there are 3 zeros.

Answer 2

Answer:

option b is the correct answer

hope it's correct

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