Question

3. If n = 2³ x 3⁴ × 5⁴×7, then the number of consecutive zeros in n, where n a natura
number, is
(a) 2
(b) 3
(c) 4
(d) 7


please explain in step by step
who answer correct and first I make you brainlist​

Answer 1

Answer:

(b) 3

Step-by-step explanation:

Given:

N=2³×3⁴×5⁴×7 (Prime Factorization)

Solution:

n=2³×3⁴×5⁴×7

n=2³x3⁴×5³×5×7

n=(2³×5³)×3⁴×5×7

n=(2×5)³×3⁴×5×7

n=10³×3⁴×5×7

So the number of consecutive zeroes in n, is 3