Math, asked by ayushijaiswal273163, 6 hours ago

3) If n = 23 x 34 x 54 x7, then then the numbers of consecutive zeros is n where n is a natural number is : 1,2,3,5​

Answers

Answered by zainuali777
0

Answer:

Answer the answer is

Step-by-step explanation:

n = 23 x 34 x 54 x 7

n = 23 x 34 x 53 x 5 x 7

n = (2 x 5)3 x 34 x 5 x 7

n = (10)3 x 34 x 5 x 7

n = 34 x 5 x 7 x 1000  

Thus, in the given natural number 'n' there are 3 zeros.

Answered by bhumika241163
3

Answer:

3

Step-by-step explanation:

Since, it is given that,

n =  {2}^{3} \times  {3}^{4} \times  {5}^{4}  \times 7 \\  =  {2}^{3}  \times  {5}^{3}  \times 5 \times  {3}^{4}  \times 7 \\  =  {(2 \times 5)}^{3}  \times 5 \times  {3}^{4}  \times 7  \\  = 5 \times  {3}^{4}  \times 7 \times  {(10)}^{3}

So, (10)^3 means the given number n will end with 3 consecutive zeroes.

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