Question

3. If n(A) = 16, n(B) = 8 and n(A U B) = 24, find n(AN B).​

Answer 1

Answer:

Given

n(A) = 16

n(B) = 8

n(A U B) = 24

To find

$\sf\: n(A \cap B)$

$\sf \: n(A U B) = n(A) + n( B) - n(A \cap B)$

$\sf \: 24 = 16 + 8 - n(A \cap B)$

$\sf \:n(A \cap B) = 16 + 8 - 24$

$\sf \:n(A \cap B) = 0$