Question

3.
If one dice rolled two times then find the probability that the sum is divisible by 2 and 7
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

The probability that the sum is divisible by 2 and 7 is $\dfrac{2}{3}$.

Step-by-step explanation:

When two dice are thrown simultaneously.

Total number of all possible outcomes =36

Let E be the event of getting that the sum of two numbers is divisible by 2 and 7.

The favorable outcomes are

(1, 1), (1, 3), (1, 5), (1,6), (2, 2),(2, 4), (2, 5), (2,6), (3,1), (3, 3), (3, 4), (3, 5), (4, 2), (4, 3),

(4, 4), (4, 6), (5,1), (5, 2) ,(5, 3), (5, 5), (6, 1), (6, 2), (6, 4) and (6,6)

Number of favorable outcomes = 24

∴P(E) = $\dfrac{Number of favorable outcomes}{Total number of all possible outcomes}$

= $\dfrac{24}{36}$

= $\dfrac{2}{3}$

Hence,  the probability that the sum is divisible by 2 and 7 is $\dfrac{2}{3}$.