Question

3
If one of the zero ep of the quadratis
Polynomial (k-1) x2 + kx+1 is -3
then the value of k is
​

Answer 1

Answer:

$k \: = \frac{4}{3}$

Step-by-step explanation:

$( k - 1) {x}^{2} + kx + 1 = 0 \\ (k - 1) \times { (- 3)}^{2} + ( - 3)k + 1 = 0 \\ 9k - 9 - 3k + 1 = 0\\ 6k - 8 = 0 \\ k = \frac{8}{6 } \\ \frac{4}{3}$