Question

3. If one root of ax2 + 2x +7 = 0 is (-2), then the value of a is:​

Answer 1

Answer:

let p(x)=$ax^{2}+2x+7$

since -2 is one of the root of p(x)

Therefore,

P(-2)=0

P(-2)=

$a(-2)^{2}+2(-2)+7=0\\4a-4+7=0\\4a+3=0\\a=\frac{-3}{4}$

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