3. If one zero of the polnumical P(x)=ax-3(a-1)x-1 is 1. then value
1
of'a' is
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Step-by-step explanation:
P(x) = ax - 3ax + 3x - 1
P(1) = a - 3a + 2
- 2a + 2 = 0
a = 1
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