Question

3. If one zero of the polynomial 1)
! kr + 1 is - 4 then the vals of is
(c)
(1)
.​

Answer 1

Answer:

ANSWER

Given −3 is the zero of the polynomial (k−1)x

2

+kx+1

So −3 must satisfy the equation (k−1)x

2

+kx+1=0

⟹(k−1)(−3)

2

+k(−3)+1=0

⟹9(k−1)−3k+1=0

⟹9k−9−3k+1=0

⟹6k=8

⟹k=

3

4

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