Question

3
If P+Q=P- and q is the angle between P and
Q, then
(A) q=0°
(C)P=0
(B)q=90°
(D) Q=0​

Answer 1

Answer:

If we solve the question by vectors,

Magnitude of P+Q=magnitude of P-Q

P^2+Q^2+2PQcosx=P^2+Q^2–2PQcosx where x is the angle between the two quantities

Therefore,

4PQcosx=0

Cosx=0

Therefore x=90 degrees or pi/2 radian

Explanation:

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