Question

(3) If P(y) = y2 - 2y + 5, find P(2).​

Answer 1

Answer:

p(2)=(2)^2-2(2)+5

4-4+5

5

p=5

Answer 2

Answer:

Given : P(y) = y^2 - 2y + 5

Solution:

P(2) = (2)^2 -2(2) + 5

= 4 - 4 + 5

= 5