Question

3
.
If pH = 3.31, then find out (H+] (Approximately)
(1) 3.39 x 104
(2) 5 x 104
(3) 3.0 x 10-3
(4) None

please give step by step solution that how 0.69 came in log ​

Answer 1

Answer:

(2)

Explanation:

pH =-log[H+]

=> -3.31 = log([H+])

=> log[H+] = -4+0.69

=> [H+] = 10^-4×10^0.69 = 5×10^-4