Question

3. If Rahit gives an interest Rs.45 for one year at 9 % per annum. What is the sum she has borrowed?


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Answer 1

Answer:

Given,

Simple interest=Rs.45

Rate of interest=9%p.a

Time=1year

We know,

S.I=100PRT

where,

P=principal

R=rate of interest

T=time

45=100P×9×1

P=945×100

P=94500

P=Rs.500

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Answer 2

Given

• Rohit gives an interest Rs.45 for one year at 9 % per annum.

We Find

• Value of principal

We know

Formula used :-

$\boxed {\red {Interest = {\frac{principal × Rate × Time}{100}}}}$

According to the question

${Interest = {\frac{principal × Rate × Time}{100}}}$

${45 = {\frac{ principal× 9 × 1}{100}}}$

${45 = {\frac{principal × 9}{100}}}$

${45 × 100 = {9p}}$

${4500 = {9p}}$

$principal = \frac{4500}{9}$

$principal = \cancel\frac{4500}{9}$

$principal = Rs \: 500$

Hence, Principal of given question is Rs $</u></strong><strong><u>\pink{500}$