Question

3 . If S+0,- →SO, , SO, + 1/202 SO3 + H20-H SO4 H, +1/20, H20 3 ; 3 AH = -298.2 → SO ; AH = -98.7 AH = -130.2 AH = -287.3 Then the enthalpy of formation of H, SO, at 298 K is - (1) -814.4 kJ (2) -650.3 kJ (3) -320.5 kJ (4) -433.5 kJ​

Answer 1

Explanation:

S+O 2 →SO 2

ΔH=−298.2 kJ/mole

SO 2 + 21 O 2 →SO 3

ΔH=−98.7 kJ/mole

SO 3 +H 2 O→H 2 SO 4 ΔH=−130.2 kJ/mole H 2 + 21 O 2 →H 2 OΔH=−287.3 kJ/mole

The formation of H

2 SO 4H 2 +S+2O 2 →H 2 SO 4 can be calculated by adding the above four equations

ΔH=−(298.2+98.7+130.2+287.3)=−814.4 kJ/mole

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