Question

3. If S= 40r2, find
(i) the value of S when r= 10
=102
(ii) the positive value of r when S = 616.
(Take a to be 22
..)

very urgent​

Answer 1

HEY MATE HERE IS YOUR ANSWER

In Case 1

✔️ R = 10 1/2

As it is in mixed form so make it improper

We get,

➡️ R = 21/2

S = pi r ^2 (Given)

So, pit values

➡️ S = 22/7 × 21/2 × 21/2

➡️ S = 11 × 21/2 × 3

➡️ S = 346.5

In Case 2

S = 616 (given)

S = pi r ^2 (Given)

616 = 22/7 × r^2

616 × 7/22 = r^2

R^2 = 196

R = /~196

R ➡️ 14

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