(3)If Sec 0=x, then tan0 =?
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Answer:
x power 2 + 1 / 2x
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Step-by-step explanation:
sec 0=x
1/cos 0=x
cos0=1/x
sin0=√[1-(1/x)^2]
sin0=√[1-(1/x^2)]
sin0=√[(x^2-1)/x^2]
sin0=√(x^2-1)/x
tan0=sin0/cos0
=[√(x^2-1)/x] /(1/x)
tan0 =√(x^2-1)
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