Question

3) If sec A = 13/12 find the value of cot A.​

Answer 1

Answer:

12/5

Step-by-step explanation:

Given sec θ = 13/12, calculate all other trigonometric ratios.

It is given that:

sec A = hypotenuse / side adjacent to ∠B = AC/AB = 13/12

Let AC = 13k and AB = 12k, where k is a positive integer.

Applying Pythagoras theorem in Δ ABC, we obtain:

AC2 = AB2 + BC2

BC2 = AC2 - AB2

BC2 = (13k)2 - (12k)2

BC2 = 169 k2 - 144 k2

BC2 = 25k2

BC = 5k

cot A = side adjacent to ∠A/ side opposite to ∠B = AB/BC = 12/5