Math, asked by rajeshreerode144, 11 months ago

(3) If sin 0 = m/n , and cos 0 = t/n then find. tan 0 and tan ( 90-0)

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Answered by keertivarma

1

Answer:

above is the answer for question

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Answered by royb83013

0

Answer:

Sin0=m/n

Cos0=t/n

tanx=sinx/cosx

tan0=m/n×n/t

tan0=m/t

tan(90-0)=cot0=1/tan0

=t/m

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