Question

3) If sin A = 4/5 Find cos A​

Answer 1

Answer:

cos A = 3/5

Step-by-step explanation:

Use pythagoras theorem for a triangle of sides 3,4,5

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Answer 2

Answer:

sin A = 4/5 = opposite/hypotenuse

cos A = adjacent/hypotenuse

$adjacent^2 + opposite^2 = hypotenuse ^2\\a^2 +(4x)^2 = (5x)^2\\a^2 = 25x^2-16x^2\\a^2 = 9x^2\\a = 3x = adjacent$

$cos A = \frac{3x}{5x}= 3/5$

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